I think I didn't do this right, doesn't make any sense, more late night math.Based on my calculations, it seemed that the reverse flow plate needed to be 30.15" wide by 76.66 (tank length of 85.5" minus 8.84", which * the RF plate width of 30.15" gives me 266.53 square inches).
I have the value of the "Area required at the end of the RF plate in square inches" (266.53 sq inches), from DaveOmak's thread. Do I have to calculate this with the ends of the tank as part of the equation, or do I just ignore it, and do simple math assuming that with a width of 30.15", I would have to reduce the length of the RF plate by the 8.84, like from the weld of the end-cap?
Busy searching to try and see if I can find other similar examples. I feel I have a decent hold on calculating the height of the RF plate, the firebox minimum volume, and other things, except for how long to make the RF plate, especially since the ends of the tank are not flat, which complicates the equation.